[Stackless] Figuring out stackless for use in Twisted

Christian Tismer tismer at tismer.com
Wed Jul 30 06:48:06 CEST 2003


Christopher Armstrong wrote:
...

> Hrm... Does that mean that I might get context switches in arbitrary
> points in my code, or only when "blocking" on a channel.send() or
> channel.receive()? If the latter, I would call that "implicit
> cooperative scheduling", not really pre-emptive. :-) I hope it's the
> latter!

Please refer to the docstrings of channel methods.
(Hoping the info is in fact there :)

If a tasklet is blocked in a channel, it is blocked.

Scheduling, whether explicitly done (stackless.schedule())
or implicitly, pre-emmptive (by a still-to-be implemented
option to stackless.run(), for instance), will never
happen for anything but the list of runnable tasklets.

The tasklets in the chain of a channel are really, really
blocked

...

>>def callUserFunction(self, f, *args, **kwargs):
>>    t = stackless.tasklet(f)
>>    c = stackless.channel()
>>    t(c, *args, **kwargs)
>>    t.run()
> 
> 
> 
> I really needed this example! Thanks. Hmm, __call__ needs a docstring
> :)

If it hasn't, then it is so because I didn't understand where to
put it.

Shorter:

c = stackless.channel()
stackless.tasklet(f)(c, *args, **kwargs).run()

ciao - chris

-- 
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