[Stackless] Question about atomic
tismer at stackless.com
Thu Jan 8 15:41:21 CET 2004
Tom Locke wrote:
> If, in a function, I do
> a = stackless.atomic()
> Then there will be no autosheduling until the object is destoryed, i.e.
> - at the end of the function
> - if I overwrite the value of 'a' or 'del a'
> What about explicit scheduling points?
Nothing at all. This is only about auto stuff.
If your code decides to schedule, it must know what it does.
> If I do a channel send/receive while the atomic is in effect, is that
> ok? Will the sceduler de-schedule me as normal? From my experiments it
> seems the answer is yes.
Sorry? This has nothing to do with auto-scheduling, this
is all explicit, including channels. The auto-stuff is
about preemptive scheduling, which is not officially there, yet.
> What about when I am re-sheduled? Is the atomic status back in effect?
The atomic status is there until it is reset. It is per-tasklet.
Christian Tismer :^) <mailto:tismer at stackless.com>
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