[Stackless] Blocked Tasklets

[Christian Tismer]

Richard wrote:
> I have no idea what the tasklet run method does.  I would use the
> scheduler run method.  Code follows.

These are totally different beasts.

Tasklet.run() makes sure that the spelled tasklet will run
immediately, instead of the current one.
A normal schedule() call has a similar effect, but if there are
other tasklets waiting in the circular queue, they might come first.

stackless.run() is something like a default scheduler which makes
the main tasklet remove itself from the runnables and wait until
all the other tasklets have finished (vanished).

I'm not sure which of these will survive the redesign which is about
to come, when writing the Stackless module for PyPy.

ciao - chris

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