[Stackless] Beginner

[Cristiano Paris]

Cristiano Paris wrote:
> ...
> What if I wanted to run JUST the tasklet I called run() upon? That is, 
> if theTasklet = t1, calling t1.run() (or whatever) should result in:
> 
> Before theTasklet.run()
> A1
> After theTasklet.run()
> Before theTasklet.run()
> A2
> After theTasklet.run()
> Before theTasklet.run()
> A1
> After theTasklet.run()
> Before theTasklet.run()
> A2
> After theTasklet.run()
> ...

I've found a way to accomplish this. I removed all the tasklets from the 
schedule queue. The code now looks like this:

------
import stackless as slp

def taskPrint(x):
   while 1:
     print x + "1"
     slp.schedule()
     print x + "2"
     slp.schedule()

t1 = slp.tasklet(taskPrint)
t2 = slp.tasklet(taskPrint)
t3 = slp.tasklet(taskPrint)

t1.setup("A")
t2.setup("B")
t3.setup("C")

t1.remove()
t2.remove()
t3.remove()

theTasklet = t1

while 1:
   print "Before theTasklet.run()"
   theTasklet.run()
   print "After theTasklet.run()"
------


Now, when I call run() on t1 I get the sequence A1/A2/A1/A2... is there 
any other (possibly better) way to do it?

Cristiano

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