[Stackless] Explicit yield/break to Preemptive Stackless Loop
bhardie at cs.usfca.edu
Wed Nov 1 20:10:22 CET 2006
I am using Stackless preemptive scheduling with a single tasklet in
order to periodically break out of the code and check for some
special conditions. This seems to be working perfectly well.
However, I have recently come across the need to have the tasklet
explicitly yield back out to the main 'stackless loop' before the
quantum has expired in order to check some conditions and potentially
do some work.
stackless.schedule() and stackless.schedule_remove() do a fine job of
yielding to the next tasklet, but it seems, in my situation of having
only a single tasklet, that it does not cause a breakout of the
Below is the 'Stackless loop' that I refer to. Is this kind of
'yield' or 'break' functionality built into Stackless? If it isn't,
I'm willing to add the functionality to the c code, but could use
some pointers on where and how to get started.
while stackless.getruncount() > 1:
t = stackless.run(QUANTUM)
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