[Stackless] must be something simple
lars van Gemerden
lars at rational-it.com
Fri May 24 11:35:50 CEST 2013
Hi,
I must be mssing something basic; why does the following not print anything:
channel = stackless.channel()
channel.preference = 1
def run(a):
print channel.send(a)
print channel.receive()
if __name__ == "__main__":
stackless.tasklet(run)("anything")
stackless.run()
If with preference = 1 the send(..) returns immediately, why doesn't
"print channel.send(a)" print "None" or something and why is 'a' never
received?
Cheers, Lars
====================================
Lars van Gemerden
lars at rational-it.com
+31 6 26 88 55 39
====================================
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