[Stackless] must be something simple

Kristján Valur Jónsson kristjan at ccpgames.com
Fri May 24 15:15:31 CEST 2013


Because channels are not queues.  If there is no one waiting to receive, then channel.send() blocks.  Channels are "rendezvous points" where one tasklets hands over a piece of data to the other.
the "preference" only matters if a transaction can take place.  In this case, if a receiver had been blocked on channel, then send would indeed not block.

K

From: stackless-bounces at stackless.com [mailto:stackless-bounces at stackless.com] On Behalf Of lars van Gemerden
Sent: 24. maí 2013 09:36
To: The Stackless Python Mailing List
Subject: Re: [Stackless] must be something simple


Hi,

I must be mssing something basic; why does the following not print anything:

channel = stackless.channel()
channel.preference = 1

def run(a):
    print channel.send(a)
    print channel.receive()

if __name__ == "__main__":

    stackless.tasklet(run)("anything")
    stackless.run()

If with preference  = 1 the send(..) returns immediately, why doesn't "print channel.send(a)" print "None" or something and why is 'a' never received?

Cheers, Lars


====================================
Lars van Gemerden
lars at rational-it.com<mailto:lars at rational-it.com>
+31 6 26 88 55 39
====================================
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