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<p class="MsoNormal"><span lang="IS">Howdy,<o:p></o:p></span></p>
<p class="MsoNormal"><span lang="IS">The time approaches when a stackless version 3.3 needs to be prepared.<o:p></o:p></span></p>
<p class="MsoNormal"><span lang="IS"><o:p> </o:p></span></p>
<p class="MsoNormal"><span lang="IS">Now, what is the right and proper way to do it in this Hg day and age?<o:p></o:p></span></p>
<p class="MsoNormal"><span lang="IS"><o:p> </o:p></span></p>
<p class="MsoNormal"><span lang="IS">Here‘s how far I can go:<o:p></o:p></span></p>
<p class="MsoListParagraph" style="text-indent:-18.0pt;mso-list:l0 level1 lfo1"><![if !supportLists]><span lang="IS"><span style="mso-list:Ignore">1)<span style="font:7.0pt "Times New Roman"">
</span></span></span><![endif]><span lang="IS">pull the cpython changes into the stackless (stackless is a superset of cpython, contining additional branches).<o:p></o:p></span></p>
<p class="MsoListParagraph" style="text-indent:-18.0pt;mso-list:l0 level1 lfo1"><![if !supportLists]><span lang="IS"><span style="mso-list:Ignore">2)<span style="font:7.0pt "Times New Roman"">
</span></span></span><![endif]><span lang="IS">(optional) update the stackless branches with whatever the corresponding cPython branches have been up to. this should be straightforward. We should probably integrate them at strategic release points, as well
as their head versions.<o:p></o:p></span></p>
<p class="MsoListParagraph" style="text-indent:-18.0pt;mso-list:l0 level1 lfo1"><![if !supportLists]><span lang="IS"><span style="mso-list:Ignore">3)<span style="font:7.0pt "Times New Roman"">
</span></span></span><![endif]><span lang="IS">Create a stackless3.3. branch, by merging stackless 3.2 into the cpython 3.3 branch. This is where I‘m not sure how to do it. Any tips?<o:p></o:p></span></p>
<p class="MsoNormal"><span lang="IS"><o:p> </o:p></span></p>
<p class="MsoNormal"><span lang="IS"><o:p> </o:p></span></p>
<p class="MsoNormal"><span lang="IS">K<o:p></o:p></span></p>
<p class="MsoListParagraph"><span lang="IS"><o:p> </o:p></span></p>
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